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An Evolute of a Circular Helix |
This means that
- $\beta(s) - \alpha(s)$ lies along the tangent to $\beta$ at $\beta(s)$.
- $\beta'(s)$ is orthogonal to $\alpha'(s)$.
Our goal is to understand what we can say about evolutes.
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An Evolute of a Circular Helix |